49x^2+14x-63=0

Solution for 49x^2+14x-63=0 equation:

49x^2+14x-63=0

a = 49; b = 14; c = -63;
Δ = b2-4ac
Δ = 142-4·49·(-63)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-112}{2*49}=\frac{-126}{98}
=-1+2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+112}{2*49}=\frac{98}{98}
=1
$